Author Question: What is the pH of the resulting solution if 40.00 mL of 0.10 M acetic acid is added to 10.00 mL of ... (Read 66 times)

darbym82 · **on:** Feb 15, 2020

Question 1

Formic acid (HCO2H, Ka = 1.8 × 10-4) is the principal component in the venom of stinging ants. What is the molarity of a formic acid solution if 25.00 mL of the formic acid solution requires 44.80 mL of 0.0567 M NaOH to reach the equivalence point?
◦ 0.0134 M
◦ 0.0316 M
◦ 0.102 M
◦ 0.0567 M

Question 2

What is the pH of the resulting solution if 40.00 mL of 0.10 M acetic acid is added to 10.00 mL of 0.10 M NaOH? Assume that the volumes of the solutions are additive. Ka = 1.8 × 10-5 for CH3CO2H

◦ 8.78
◦ 4.27
◦ 5.22
◦ 9.73

kingdude89 · **Reply #1 on:** Feb 15, 2020

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