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Author Question: The iron content of foods can be determined by dissolving them in acid (forming Fe3+), reducing the ... (Read 28 times)

oliviahorn72

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on: Feb 15, 2020

Question 1

What is the reduction half-reaction for the following overall cell reaction?

Ni2+(aq) + 2 Ag(s) → Ni(s) + 2 Ag+(aq)


◦ Ni2+(aq) + 2 e- → Ni(s)
◦ Ni2+(aq) + e- → Ni(s)
◦ Ag(s) + e- → Ag+(aq)
◦ Ag+(aq) + e- → Ag(s)

Question 2

The iron content of foods can be determined by dissolving them in acid (forming Fe3+), reducing the iron(III) to iron(II), and titrating with cerium(IV):

Fe2+(aq) + Ce4+(aq) → Fe3+(aq) + Ce3+(aq).


Identify the two half-reactions in the above reaction.
◦
oxidation half-reactionreduction half-reaction
Fe2+(aq) + e-→ Fe3+(aq)Ce4+(aq) → Ce3+(aq) + e-

◦
oxidation half-reactionreduction half-reaction
Ce4+(aq) + e- → Ce3+(aq)Fe2+(aq) → Fe3+(aq) + e-

◦
oxidation half-reactionreduction half-reaction
Ce4+(aq) → Ce3+(aq) + e-Fe2+(aq) + e- → Fe3+(aq)

◦
oxidation half-reactionreduction half-reaction
Fe2+(aq) → Fe3+(aq) + e-Ce4+(aq) + e- → Ce3+(aq)
Chemistry ¦ McMurry, Fay, Robinson ¦ 7th Edition
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Marked as best answer by oliviahorn72 on Feb 15, 2020

olderstudent

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Reply #1 on: Feb 15, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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oliviahorn72

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Reply 2 on: Feb 15, 2020
Great answer, keep it coming :)

xoxo123

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Reply 3 on: Yesterday
Wow, this really help

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