The iron content of foods can be determined by dissolving them in ...

[oliviahorn72]

Question 1

What is the reduction half-reaction for the following overall cell reaction?

Ni2+(aq) + 2 Ag(s) → Ni(s) + 2 Ag+(aq)

◦ Ni2+(aq) + 2 e- → Ni(s)
◦ Ni2+(aq) + e- → Ni(s)
◦ Ag(s) + e- → Ag+(aq)
◦ Ag+(aq) + e- → Ag(s)

Question 2

The iron content of foods can be determined by dissolving them in acid (forming Fe3+), reducing the iron(III) to iron(II), and titrating with cerium(IV):

Fe2+(aq) + Ce4+(aq) → Fe3+(aq) + Ce3+(aq).

Identify the two half-reactions in the above reaction.
◦

oxidation half-reaction

reduction half-reaction

Fe2+(aq) + e-→ Fe3+(aq)

Ce4+(aq) → Ce3+(aq) + e-

◦

oxidation half-reaction

reduction half-reaction

Ce4+(aq) + e- → Ce3+(aq)

Fe2+(aq) → Fe3+(aq) + e-

◦

oxidation half-reaction

reduction half-reaction

Ce4+(aq) → Ce3+(aq) + e-

Fe2+(aq) + e- → Fe3+(aq)

◦

oxidation half-reaction

reduction half-reaction

Fe2+(aq) → Fe3+(aq) + e-

Ce4+(aq) + e- → Ce3+(aq)

[olderstudent]

A FREE account is required to view all solutions! Click to Register

Login with Facebook Login with Google Login with Email

Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.

Answer Preview

Only 29% of students answer this correctly

[oliviahorn72]

Thanks for the timely response, appreciate it

[miss_1456@hotmail.com]

Excellent