Author Question: Suppose that in one town 12% of women and 8% of men are vegetarians. Let 1 denote the proportion of ... (Read 103 times)

cagreen833 · **on:** Apr 7, 2020

Suppose that in one town 12% of women and 8% of men are vegetarians. Let

₁ denote the proportion of vegetarians among a sample of 200 women selected randomly from the town. Let

₂ denote the proportion of vegetarians among a sample of 100 men selected randomly from the town. What is the distribution of

₁ -

₂ and what are its mean and standard deviation? Assume that the two samples are independent.
◦

₁ -

₂ is approximately normally distributed with a mean of 0.04 and a standard deviation of 0.0356.
◦

₁ -

₂ is exactly normally distributed with a mean of 0.4 and a standard deviation of 0.0356.
◦

₁ -

₂ is exactly normally distributed with a mean of 0.4 and a standard deviation of 0.00127.
◦

₁ -

₂ is approximately normally distributed with a mean of 0.04 and a standard deviation of 0.00127.

janeli1 · **Reply #1 on:** Apr 7, 2020

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