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Author Question: The UCL and LCL for an -chart are 25 and 15 respectively. The central line is 20, and the process ... (Read 46 times)

Arii_bell

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on: Apr 18, 2020
The UCL and LCL for an -chart are 25 and 15 respectively. The central line is 20, and the process variability is considered to be in statistical control. The results of the next six sample means are 18, 23, 17, 21, 24, and 16. What should you do?
◦ Nothing; the process is in control.
◦ Explore the assignable causes because there is a trend.
◦ Explore the assignable causes because the second and fifth samples are above the mean.
◦ Explore the assignable causes because there is a run.
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Marked as best answer by Arii_bell on Apr 18, 2020

nickk12214

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Reply #1 on: Apr 18, 2020
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Arii_bell

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Reply 2 on: Apr 18, 2020
Great answer, keep it coming :)

bbburns21

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Reply 3 on: Yesterday
Gracias!

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