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Author Question: A baseball pitcher throws a baseball with an initial speed of 127 feet per second ... (Read 196 times)

abarnes

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on: Feb 28, 2021
Solve the problem.

A baseball pitcher throws a baseball with an initial speed of 127 feet per second at an angle of 20° to the horizontal. The ball leaves the pitcher's hand at a height of 4 feet. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the maximum height of the ball?
◦ x = 119.34t, y = -16t2 + 43.43t + 4
2.804 sec, 1.357 sec,
33.471 feet
◦ x = 119.34t, y = -16t2 + 43.43t + 4
5.238 sec, 1.357 sec,
239.771 feet
◦ x = 119.34t, y = -16t2 + 43.43t + 4
2.619 sec, 1.357 sec,
3.997 feet
◦ x = 119.34t, y = -16t2 + 43.43t + 4
5.607 sec, 1.357 sec,
29.471 feet
Precalculus ¦ Sullivan ¦ 10th Edition
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Marked as best answer by abarnes on Feb 28, 2021

covalentbond

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Reply #1 on: Feb 28, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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abarnes

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Reply 2 on: Feb 28, 2021
Excellent

fatboyy09

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Reply 3 on: Yesterday
Wow, this really help

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