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Author Question: If a molecule demonstrates paramagnetism, then:I.the substance can have both paired and unpaired ... (Read 67 times)

bobthebuilder

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on: Mar 21, 2021
If a molecule demonstrates paramagnetism, then:
 
I.
the substance can have both paired and unpaired electrons.
 
II.
the bond order is not a whole number.
 
III.
it can be determined by drawing a Lewis structure.
 
IV.
it must be an ion.
 

​


◦ I, II
◦ I, II, IV
◦ II, III
◦ I only
◦ All of the statements are correct.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by bobthebuilder on Mar 21, 2021

fromAlphatoOmega22

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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bobthebuilder

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Reply 2 on: Mar 21, 2021
Wow, this really help

AISCAMPING

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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