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Author Question: You mix 280.0 mL of 1.20 M lead(II) nitrate with 300.0 mL of 1.80 M potassium iodide. The lead(II) ... (Read 52 times)

ETearle

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on: Mar 21, 2021
You mix 280.0 mL of 1.20 M lead(II) nitrate with 300.0 mL of 1.80 M potassium iodide. The lead(II) iodide is insoluble. Which of the following is false?

◦ The final concentration of Pb2+ ions is 0.114 M.
◦ You form 124 g of lead(II) iodide.
◦ The final concentration of K+ is 0.931 M.
◦ The final concentration of NO3– is 0.931 M.
◦ All of these are true.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by ETearle on Mar 21, 2021

Pariscourtney

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ETearle

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Reply 2 on: Mar 21, 2021
Wow, this really help

amandalm

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Reply 3 on: Yesterday
Gracias!

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