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Author Question: For the equilibrium system:CO2(g) + H2(g) CO(g) + H2O(g) H = +42 kJ/molK equals 1.6 at 1260 K. If ... (Read 58 times)

anjilletteb

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on: Mar 21, 2021
For the equilibrium system:
CO2(g) + H2(g) CO(g) + H2O(g)     H = +42 kJ/mol
K equals 1.6 at 1260 K. If 0.15 mol each of CO2, H2, CO, and H2O (all at 1260 K) were placed in a 1.0-L thermally insulated vessel that was also at 1260 K, then as the system came to equilibrium:

◦ The temperature would decrease and the mass of CO2 would increase.
◦ The temperature would decrease and the mass of CO2 would decrease.
◦ The temperature would remain constant and the mass of CO2 would increase.
◦ The temperature would increase and the mass of CO2 would increase.
◦ The temperature would increase and the mass of CO2 would decrease.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by anjilletteb on Mar 21, 2021

verrinzo

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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anjilletteb

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Reply 2 on: Mar 21, 2021
Thanks for the timely response, appreciate it

matt95

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Reply 3 on: Yesterday
Wow, this really help

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