Question 1
A 100.0-mL sample of 0.2 M (CH3)3N (Kb = 5.30 × 10–5) is titrated with 0.2 M HCl. What is the pH at the equivalence point?
◦
2.6◦
8.6◦
10.7◦
5.4◦
7.0Question 2
A 100.0-mL sample of 0.583 M H2A (diprotic acid) is titrated with 0.200 M NaOH. After 125.0 mL of 0.200 M NaOH has been added, the pH of the solution is 4.50. Calculate Ka1 for H2A.
◦
4.2 × 10–10◦
4.5◦
2.4 × 10–5◦
0.65◦
None of these are correct.