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Author Question: The function f(x) = (x3 - 5)e-x has one critical point in the interval x > 0. Find this critical ... (Read 63 times)

shofmannx20

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on: May 26, 2021

Question 1

Newton's Method with the initial approximation x1 = 1 is used to approximate the real root of the equation  x3 + 3x - 1 = 0.  Determine the value of  x3, the third iteration of Newton's Method.
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Question 2

The function  f(x) = (x3 - 5)e-x  has one critical point in the interval  x > 0.  Find this critical point with error within 0.005 by applying Newton's Method to an appropriate function.
◦ 3.4259
◦ 3.2240
◦ 3.1278
◦ 3.4023
◦ none of the above
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Marked as best answer by shofmannx20 on May 26, 2021

Ksh22

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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shofmannx20

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Reply 2 on: May 26, 2021
Excellent

kishoreddi

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Reply 3 on: Yesterday
:D TYSM

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