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Author Question: Find the length of the arc y = ln(sec x) between x = 0 and x = . (Read 27 times)

neverstopbelieb

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on: May 26, 2021

Question 1

Find the length of the curve  y = x2 - ln +7  from x = -2  to x = -1.
◦ - ln(2)
◦ ln(2) -
◦ - ln(32)
◦ + ln(2)
◦ - ln(2)

Question 2

Find the length of the arc  y = ln(sec x)  between  x = 0 and x = .
◦ ln() units
◦ ln(1 + ) units
◦ ln(2 + ) units
◦ ln( - 1) units
◦ ln(2 - ) units
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Marked as best answer by neverstopbelieb on May 26, 2021

Rilsmarie951

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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neverstopbelieb

  • Member
  • Posts: 534
Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

essyface1

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  • Posts: 347
Reply 3 on: Yesterday
Great answer, keep it coming :)

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