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Author Question: Describe the graph of the polar equation r = 6(sin + cos ). (Read 140 times)

itsmyluck

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on: May 26, 2021

Question 1

Convert r = -8cosθ  into Cartesian coordinates.
◦ x2 - y2 = 4x
◦ x2 + y2 = 4x
◦ 2x2 + 4y2 = -4x
◦ x2 + y2 = -8x
◦ x2 - y2 = -8x

Question 2

Describe the graph of the polar equation r = 6(sin θ + cos θ).
◦ Circle with centre at (3, 3) and radius 6
◦ Straight line with intercepts  (3, 0)  and  (0, 3)
◦ Circle with centre at (3, 3) and radius 3
◦ Circle with centre at (3, 3) and radius
◦ Straight line with intercepts  (6, 0)  and  (0, 6)
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Marked as best answer by itsmyluck on May 26, 2021

Anna

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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itsmyluck

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Reply 2 on: May 26, 2021
YES! Correct, THANKS for helping me on my review

pangili4

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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