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Author Question: Using the known geometric series representation = xn, valid for -1 < x < 1, find a power series ... (Read 73 times)

tingc95

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on: May 26, 2021

Question 1

By suitably manipulating the geometric series =  ,  -1 < x < 1, you can calculate the sum of the series . Use this method to evaluate the sum .
◦ 6
◦ 10
◦ 8
◦ 4
◦ none of the above

Question 2

Using the known geometric series representation   = xn,  valid for  -1 < x < 1,  find a power series representation for  f(x) = ln(2 + x)  in powers of  x - 1. On what interval does the series converge to  f(x)?
◦ f(x)  = ln 3  +   n,  for  -2 < x ≤ 4
◦ f(x)  = ln 2  +   n,  for  -1 < x < 3
◦ f(x)  = ln 2  +   n,  for  -1 < x ≤ 3
◦ f(x)  = ln 3  +   n,  for  -0 < x ≤ 2
◦ none of the above
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Marked as best answer by tingc95 on May 26, 2021

catron30

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Reply #1 on: May 26, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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tingc95

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Reply 2 on: May 26, 2021
Wow, this really help

dyrone

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Reply 3 on: Yesterday
Excellent

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