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Author Question: Solve the initial-value problem (x2 - 1)y" + xy' - y = 0, y(0) = 1, y'(0) = 0 in the form of a power ... (Read 175 times)

james0929

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on: May 27, 2021

Question 1

Solve the initial-value problem y" + xy' + y = 0,  y(0) = 0,  y'(0) = 1  in the form of a power series in powers of  x.
◦ y  =  
◦ y  =  
◦ y  =  
◦ y  =  
◦ y  =  

Question 2

Solve the initial-value problem  (x2 - 1)y" + xy' - y = 0,  y(0) = 1,  y'(0) = 0  in the form of a power series in powers of  x.
◦ 1 + x2n
◦ 1 - x2n
◦ 1 - x2n
◦ 1 + x2n
◦ 1 - x2n
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Marked as best answer by james0929 on May 27, 2021

gasdhashg

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Reply #1 on: May 27, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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james0929

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Reply 2 on: May 27, 2021
YES! Correct, THANKS for helping me on my review

kjohnson

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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