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Author Question: Determine where the given function is increasing and where it is decreasing.f(x) = x2(6 - x)2 (Read 25 times)

ereecah

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on: Jun 16, 2021

Question 1

Determine where the given function is increasing and where it is decreasing. 

f(x) = (x - 2)1/3 + 6
◦ Decreasing on (-∞, ∞)
◦ Decreasing on (-∞, 2), increasing on (2, ∞)
◦ Increasing on (-∞, ∞)
◦ Increasing on (-∞, 2), decreasing on (2, ∞)

Question 2

Determine where the given function is increasing and where it is decreasing. 

f(x) = x2(6 - x)2
◦ Decreasing on (-∞, 0) and , increasing on  and (6, ∞)
◦ Decreasing on (-∞, 0) and (6, ∞), increasing on (0, 6)
◦ Increasing on (-∞, 0) and , decreasing on  and (6, ∞)
◦ Decreasing on (-∞, 0) and , increasing on 
Calculus and Its Applications ¦ Bittinger, Ellenbogen, Surgent ¦ 11th Edition
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Marked as best answer by ereecah on Jun 16, 2021

Liddy

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Reply #1 on: Jun 16, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ereecah

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Reply 2 on: Jun 16, 2021
Wow, this really help

samiel-sayed

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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