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Author Question: A 0.920-gram sample of magnesium is allowed to burn in 0.321 g of oxygen gas. The sole product is ... (Read 39 times)

jeatrice

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on: Jul 8, 2021

Question 1

57.7 g Ni contains how many atoms?
◦ 6.13 × 1023 atoms
◦ 3.47 × 1023 atoms
◦ 5.92 × 1023 atoms
◦ 1.24 × 1024 atoms
◦ 0.983 atoms

Question 2

A 0.920-gram sample of magnesium is allowed to burn in 0.321 g of oxygen gas.  The sole product is magnesium oxide.  After the reaction, no oxygen remains and 0.809 g of magnesium oxide has been formed.  What mass of magnesium is left unreacted?
◦ 0.210 g
◦ 0.432 g
◦ 1.408 g
◦ 0.111 g
◦ 0.488 g
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by jeatrice on Jul 8, 2021

strudel15

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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jeatrice

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Reply 2 on: Jul 8, 2021
Wow, this really help

tranoy

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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