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Author Question: Determine the enthalpy change in the following equation: 2/3 H2S(g) + O2(g) 2/3 SO2(g) + 2/3 H2O(l) ... (Read 18 times)

appyboo

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on: Jul 8, 2021

Question 1

Determine the enthalpy change in the following equation:

2 NH3(g) → N2(g) + 3 H2(g)
ΔfH° NH3(g) = -46.11 kJ/mol

◦ 92.22 kJ/mol
◦ 46.11 kJ/mol
◦ 5.42 kJ/mol
◦ -92.22 kJ/mol
◦ -46.11 kJ/mol

Question 2

Determine the enthalpy change in the following equation:

2/3 H2S(g) + O2(g) → 2/3 SO2(g) + 2/3 H2O(l)
ΔfH° H2O(l) = -285.8 kJ/mol
ΔfH° H2S(g) = -20.63 kJ/mol
ΔfH° SO2(g) = -296.8 kJ/mol

◦ -562 kJ/mol
◦ -375 kJ/mol
◦ 375 kJ /mol
◦ -402 kJ/mol
◦ 402 kJ/mol
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by appyboo on Jul 8, 2021

mjenn52

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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appyboo

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)

sultana.d

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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