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Author Question: Given H2(g) + (1/2)O2(g) H2O(l), H = 286 kJ/mol, determine the standard enthalpy change for the ... (Read 55 times)

Rafic Kaaki

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on: Nov 5, 2023

Question 1

Given  2Al(s) + (3/2)O2(g) → Al2O3(s),  ΔH°f = –1,670 kJ/mol for Al2O3 (s).
Determine ΔH° for the reaction 2Al2O3(s) → 4Al(s) + 3O2(g).
◦ –3,340 kJ/mol
◦ –1,670 kJ/mol
◦ –835 kJ/mol
◦ 1,670 kJ/mol
◦ 3,340 kJ/mol

Question 2

Given H2(g) + (1/2)O2(g) → H2O(l), ΔH° = –286 kJ/mol, determine the standard enthalpy change for the reaction 2H2O(l) → 2H2(g) + O2(g).
◦ ΔH° = –286 kJ/mol
◦ ΔH° = +286 kJ/mol
◦ ΔH° = –572 kJ/mol
◦ ΔH° = +572 kJ/mol
◦ ΔH° = –143 kJ/mol
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by Rafic Kaaki on Nov 5, 2023

Jaclyn92G6

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Rafic Kaaki

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

shailee

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Reply 3 on: Yesterday
:D TYSM

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