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Author Question: How much heat is needed to raise the temperature of 5.28 gal of water from 25.0 C to 88.0 C (1 gal = 3.785 L)? (Read 49 times)

gonzo233

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on: Jul 8, 2021

Question 1

How much heat is involved in the complete combustion of 2.50 kg propane, C3H8?

ΔrHcomb = -2219 kJ/mol

◦ 1.26 × 105 kJ
◦ 5.55 × 103 kJ
◦ 126 kJ
◦ 503 kJ
◦ 49.7 kJ

Question 2

How much heat is needed to raise the temperature of 5.28 gal of water from 25.0 °C to 88.0 °C
(1 gal = 3.785 L)?
◦ 5260 kJ
◦ 997 kJ
◦ 1390 kJ
◦ 316 kJ
◦ 133 kJ
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by gonzo233 on Jul 8, 2021

chloejackso

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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gonzo233

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Reply 2 on: Jul 8, 2021
Wow, this really help

bigcheese9

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Reply 3 on: Yesterday
Gracias!

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