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Author Question: For the following voltaic cell, determine the [Cl-] when PCl2 = 0.500 atm, [Zn2+] = 1.77 10-2 M, ... (Read 49 times)

notis

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For the following voltaic cell, determine the [Cl-] when PCl2 = 0.500 atm, [Zn2+] = 1.77 × 10-2 M, and Ecell = 2.250 V. The half-reactions at 25 °C are:

Cl2(g) + 2 e-→ 2 Cl-(aq) = +1.358 V
Zn2+(aq) + 2 e-→ Zn(s) = -0.763 V
Zn(s) Zn2+(aq) Cl-(aq), Cl2(g) Pt(s)

◦ 5.48 × 10-6 M
◦ 2.32 × 10-3 M
◦ 0.0296 M
◦ 0.0939 M
◦ 0.0352 M


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Marked as best answer by notis on Jul 8, 2021

BUTTHOL369

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notis

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Reply 2 on: Jul 8, 2021
Excellent


amandanbreshears

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Reply 3 on: Yesterday
Great answer, keep it coming :)

 

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