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Author Question: Carbon-14, which is present in all living tissue, radioactively decays via a first-order process. A ... (Read 53 times)

ENagel

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on: Jul 8, 2021

Question 1

Calculate rate constant k for a first order reaction with a half-life of 75.0 min.
◦ 52.0 min-1
◦ 1.54 × 10-4 min-1
◦ 1.33 × 10-2 min-1
◦ 9.24 × 10-3 min-1
◦ 2.67 × 10-2 min-1

Question 2

Carbon-14, which is present in all living tissue, radioactively decays via a first-order process. A one-gram sample of wood taken from a living tree gives a rate for carbon-14 decay of 13.6 counts per minute. If the half-life for carbon-14 is 5720 years, how old is a wood sample that gives a rate for carbon-14 decay of 11.9 counts per minute?
◦ 5.3 × 102 yr
◦ 7.6 × 102 yr
◦ 1.1 × 103 yr
◦ 9.4 × 103 yr
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by ENagel on Jul 8, 2021

macmac

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ENagel

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Reply 2 on: Jul 8, 2021
Wow, this really help

essyface1

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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