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Author Question: When [Ni(NH3)4]2+ is treated with concentrated HCl(aq), two compounds having the same formula, ... (Read 35 times)

Kikoku

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on: Jul 8, 2021
When [Ni(NH3)4]2+ is treated with concentrated HCl(aq), two compounds having the same formula, [Ni(NH3)4Cl2], designated I and II, are formed. Compound I can be converted to compound II by boiling it in dilute HCl(aq). A solution of I reacts with oxalic acid, H2C2O4, to form [Ni(NH3)4(C2O4)]. Compound II does not react with oxalic acid. Compound II is:
◦ the cis isomer
◦ tetrahedral in shape
◦ the trans isomer
◦ the same as compound I
◦ octahedral in shape
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by Kikoku on Jul 8, 2021

tmlewis4706

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Kikoku

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Reply 2 on: Jul 8, 2021
Excellent

laurnthompson

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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