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Author Question: If 14.2 g of Al(NO3)3 is dissolved in 655g of water, what is the boiling point of the solution ... (Read 47 times)

meganh99

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on: Nov 5, 2023

Question 1

How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
◦ 769 g
◦ 36.2 g
◦ 100. g
◦ 0.157 g
◦ 157 g

Question 2

If 14.2 g of Al(NO3)3 is dissolved in 655g of water, what is the boiling point of the solution (assume 100% dissociation, Kb (H2O) = 0.52 °C/m)?
◦ 99.8°C
◦ 99.9°C
◦ 100.1°C
◦ 100.2°C
◦ 100.4°C
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by meganh99 on Nov 5, 2023

sakura282000

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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meganh99

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Reply 2 on: Nov 5, 2023
Gracias!

nathang24

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Reply 3 on: Yesterday
:D TYSM

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