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Author Question: 25.0 mL of a 0.100 M solution of NH3 is titrated with 0.150M HCl. After 10.0 mL of the HCl has been ... (Read 20 times)

markburs

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on: Nov 5, 2023
25.0 mL of a 0.100 M solution of NH3 is titrated with 0.150M HCl. After 10.0 mL of the HCl has been added, the resultant solution is:
◦ Basic and before the equivalence point
◦ Basic and after the equivalence point
◦ Acidic and before the equivalence point
◦ Acidic and after the equivalence point
◦ Neutral and at the equivalence point
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by markburs on Nov 5, 2023

Jaclyn92G6

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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markburs

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Reply 2 on: Nov 5, 2023
Great answer, keep it coming :)

robbielu01

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

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