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Author Question: For the reaction SbCl5(g) SbCl3(g) + Cl2(g), Gf (SbCl5) = 334.34 kJ/mol Gf (SbCl3) = 301.25 ... (Read 9 times)

dongbo

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on: Nov 5, 2023

Question 1

For the reaction SbCl5(g) SbCl3(g) + Cl2(g),
         ΔG°f (SbCl5) = –334.34 kJ/mol
         ΔG°f (SbCl3) = –301.25 kJ/mol
         ΔH°f (SbCl5) = –394.34 kJ/mol
         ΔH°f (SbCl3) = –313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) for this reaction at 298 K.

Question 2

For the reaction SbCl5(g) SbCl3(g) + Cl2(g),
         ΔG°f (SbCl5) = –334.34 kJ/mol
         ΔG°f (SbCl3) = –301.25 kJ/mol
         ΔH°f (SbCl5) = –394.34 kJ/mol
         ΔH°f (SbCl3) = –313.80 kJ/mol
Calculate the value of the equilibrium constant (Kp) at 800 K and 1 atm pressure.
Chemistry ¦ Chang, Goldsby ¦ 11th Edition
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Marked as best answer by dongbo on Nov 5, 2023

hillard sane

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Reply #1 on: Nov 5, 2023
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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dongbo

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Reply 2 on: Nov 5, 2023
YES! Correct, THANKS for helping me on my review

laurnthompson

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Reply 3 on: Yesterday
Wow, this really help

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