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Author Question: For the reaction: 2 N2O5(g) 4 NO2(g) + O2(g) at the time when N2O5 is being consumed at a rate of ... (Read 50 times)

@Brianna17

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Question 1

For the reaction 2 HgCl2 + C2O42-→ products, data are:

[HgCl2]0 (in M) 0.0836 0.0836 0.0418
[C2O42-]0 (in M) 0.202 0.404 0.404
rate (M/hr) 0.26 1.04 0.53

The rate law is Rate = k[HgCl2]x[C2O42-]y. Thus:
◦ x = 2, y = 1
◦ x = 2, y = 2
◦ x = 1, y = 2
◦ x = 1, y = 1
◦ x = 0, y = 2

Question 2

For the reaction: 2 N2O5(g) → 4 NO2(g) + O2(g) at the time when N2O5 is being consumed at a rate of 1.2 × 10-4 M/s, what is the rate at which O2 is being formed?
◦ 1.2 × 10-4 M/s
◦ 2.4 × 10-4 M/s
◦ 6.0 × 10-5 M/s
◦ 3.0 × 10-5 M/s
◦ 4.8 × 10-4 M/s


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Marked as best answer by @Brianna17 on Jul 8, 2021

Perkypinki

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@Brianna17

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)


AngeliqueG

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Reply 3 on: Yesterday
Wow, this really help

 

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