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Author Question: S(x) = -x3 + 6x2 + 288x + 4000, 4 x 20 is an approximation to the number of salmon swimming ... (Read 263 times)

tichca

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on: Oct 21, 2019
S(x) = -x3 + 6x2 + 288x + 4000, 4 ≤ x ≤ 20 is an approximation to the number of salmon swimming upstream to spawn, where x represents the water temperature in degrees Celsius. Find the temperature that produces the maximum number of salmon.
◦ 12°C
◦ 20°C
◦ 4°C
◦ 8°C
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Marked as best answer by tichca on Oct 21, 2019

sabina576

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Reply #1 on: Oct 21, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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P68T

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Reply #2 on: Oct 21, 2019
S(x) = -x3 + 3x2 + 189x + 1200, 2 ≤ x ≤ 9 is an approximation to the number of salmon swimming upstream to spawn, where x represents the water temperature in degrees Celsius. Find the temperature that produces the maximum number of salmon.
◦ 8°C
◦ 3°C
◦ 9°C
◦ 2°C


jsm54321

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Reply #3 on: Oct 21, 2019
9°C


P68T

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Reply #4 on: Oct 21, 2019
Excellent


jsm54321

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Reply #5 on: Oct 21, 2019
Great! Please up vote :D


oliviahorn72

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Reply #6 on: Oct 21, 2019
S(x) = -x3 - 45x2 + 525x + 1429, 0 ≤ x ≤ 15 is an approximation to the number of salmon swimming upstream to spawn, where x represents the water temperature in degrees Celsius. Find the temperature that produces the maximum number of salmon.
◦ 5°C
◦ 12.5°C
◦ 10°C
◦ 0°C


Awesome

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Reply #7 on: Oct 21, 2019
5°C


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