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Author Question: Determine the electron geometry (eg) and molecular geometry (mg) of BCl3. (Read 59 times)

londonang

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on: Nov 18, 2019

Question 1

Give the approximate bond angle between two equatorial positions for a molecule with a trigonal bipyramidal geometry.
◦ 109.5°
◦ 180°
◦ 120°
◦ 105°
◦ 90°

Question 2

Determine the electron geometry (eg) and molecular geometry (mg) of BCl3.
◦ eg = trigonal planar, mg = trigonal planar
◦ eg = tetrahedral, mg = trigonal planar
◦ eg = trigonal bipyramidal, mg = trigonal bipyramidal
◦ eg = trigonal planar, mg = bent
◦ eg = tetrahedral, mg = trigonal pyramidal
Chemistry: A Molecular Approach (Canadian) ¦ Tro, Fridgen, Shaw ¦ 2nd Edition
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Marked as best answer by londonang on Nov 18, 2019

shailee

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Reply #1 on: Nov 18, 2019
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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londonang

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Reply 2 on: Nov 18, 2019
Wow, this really help

hollysheppard095

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Reply 3 on: Yesterday
:D TYSM

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