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Author Question: Consider the molecule below. Determine the molecular geometry at each of the three labelled atoms. (Read 43 times)

Metfan725

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Question 1

Consider the molecule below. Determine the molecular geometry at each of the two labelled carbons.



◦ C1 = trigonal planar, C2 = bent
◦ C1 = tetrahedral, C2 = linear
◦ C1 = trigonal pyramidal, C2 = seesaw
◦ C1 = bent, C2 = trigonal planar
◦ C1 = trigonal planar, C2 = tetrahedral

Question 2

Consider the molecule below. Determine the molecular geometry at each of the three labelled atoms.



◦ 1 = trigonal planar, 2 = tetrahedral, 3 = tetrahedral
◦ 1 = trigonal planar, 2 = trigonal pyramidal, 3 = trigonal pyramidal
◦ 1 = tetrahedral, 2 = tetrahedral, 3 = tetrahedral
◦ 1 = tetrahedral, 2 = tetrahedral, 3 = trigonal planar
◦ 1 = trigonal planar, 2 = tetrahedral, 3 = trigonal pyramidal


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Marked as best answer by Metfan725 on Nov 18, 2019

sultansheikh

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Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Metfan725

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Reply 2 on: Nov 18, 2019
Wow, this really help


tranoy

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Reply 3 on: Yesterday
YES! Correct, THANKS for helping me on my review

 

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