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Author Question: Consider the reaction:2ClF3(g) + 2NH3(g) N2(g) + 6HF(g) + Cl2(g)When calculating the Hrxn, why is ... (Read 533 times)

asd123

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on: Mar 21, 2021

Question 1

Consider the reaction:
   
When a 19.2-g sample of ethyl alcohol (molar mass = 46.07 g/mol) is burned, how much energy is released as heat?

◦ 0.417 kJ
◦ 0.571 kJ
◦ 5.71 × 102 kJ
◦ 2.63 × 104 kJ
◦ 2.40 kJ

Question 2

Consider the reaction:

2ClF3(g) + 2NH3(g) → N2(g) + 6HF(g) + Cl2(g)

When calculating the ΔH°rxn, why is the ΔHf° for N2 not important?


◦ Because nitrogen is in its standard elemental state and no energy is needed for this product to exist.
◦ Because any element or compound in the gaseous state requires a negligible amount of energy to exist.
◦ Because the products are not included when calculating ΔH°rxn.
◦ Because nitrogen is in its elemental state and does not contribute to the reaction itself.
◦ Two of these statements explain why N2is not important when calculating ΔH°rxn.
Chemistry: An Atoms First Approach ¦ Zumdahl, DeCoste ¦ 3rd Edition
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Marked as best answer by asd123 on Mar 21, 2021

onowka

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Reply #1 on: Mar 21, 2021
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asd123

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Reply 2 on: Mar 21, 2021
:D TYSM

adammoses97

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Reply 3 on: Yesterday
Excellent

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