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Author Question: Consider the reaction:2ClF3(g) + 2NH3(g) N2(g) + 6HF(g) + Cl2(g)When calculating the Hrxn, why is ... (Read 539 times)

asd123

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Question 1

Consider the reaction:
   
When a 19.2-g sample of ethyl alcohol (molar mass = 46.07 g/mol) is burned, how much energy is released as heat?

0.417 kJ
0.571 kJ
5.71 × 102 kJ
2.63 × 104 kJ
2.40 kJ

Question 2

Consider the reaction:

2ClF3(g) + 2NH3(g) → N2(g) + 6HF(g) + Cl2(g)

When calculating the ΔH°rxn, why is the ΔHf° for N2 not important?


Because nitrogen is in its standard elemental state and no energy is needed for this product to exist.
Because any element or compound in the gaseous state requires a negligible amount of energy to exist.
Because the products are not included when calculating ΔH°rxn.
Because nitrogen is in its elemental state and does not contribute to the reaction itself.
Two of these statements explain why N2is not important when calculating ΔH°rxn.


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Marked as best answer by asd123 on Mar 21, 2021

onowka

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asd123

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Reply 2 on: Mar 21, 2021
Great answer, keep it coming :)


at

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

 

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