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Author Question: he enthalpy of vaporization of isopropanol is 44.00 kJ/mol at its boiling point (82.3C). Calculate ... (Read 114 times)

ericka1

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on: Mar 21, 2021

Question 1

Τhe enthalpy of vaporization of ethanol is 38.56 kJ/mol at its boiling point (78.4°C). Calculate the value of ΔS when 1.00 mole of ethanol is vaporized at 78.4°C and 1.00 atm.

◦ 0
◦ 4.92 × 102 J/K·mol
◦ 1.10 × 102 J/K·mol
◦ –1.10 × 102 J/K·mol
◦ –4.92 × 102 J/K·mol

Question 2

Τhe enthalpy of vaporization of isopropanol is 44.00 kJ/mol at its boiling point (82.3°C). Calculate the value of ΔSsurr when 1.00 mole of isopropanol is vaporized at 82.3°C and 1.00 atm.

◦ 0
◦ 5.35 × 102 J/K·mol
◦ 1.24 × 102 J/K·mol
◦ –1.24 × 102 J/K·mol
◦ –5.35 × 102 J/K·mol
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Marked as best answer by ericka1 on Mar 21, 2021

iman

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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ericka1

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Reply 2 on: Mar 21, 2021
Excellent

matt95

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Reply 3 on: Yesterday
Great answer, keep it coming :)

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