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Author Question: An excess of finely divided iron is stirred up with a solution that contains Cu2+ ion, and the ... (Read 65 times)

Jkov05

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on: Mar 21, 2021
An excess of finely divided iron is stirred up with a solution that contains Cu2+ ion, and the system is allowed to come to equilibrium. The solid materials are then filtered off and electrodes of solid copper and solid iron are inserted into the remaining solution. What is the value of the ratio [Fe2+]/[Cu2+] at 25°C?
The following standard reduction potentials apply:
 
Fe2+(aq) + 2e– Fe(s)
E° = –0.44 V
 
Cu2+(aq) + 2e– Cu(s)
E° = +0.34 V
 

​


◦ 1
◦ 0
◦ 2.5 × 1026

​


◦ 4.4 × 10–27

​


◦ None of these are correct.
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Marked as best answer by Jkov05 on Mar 21, 2021

mammy1697

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Reply #1 on: Mar 21, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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Jkov05

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Reply 2 on: Mar 21, 2021
Excellent

blakcmamba

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Reply 3 on: Yesterday
:D TYSM

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