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Author Question: Given the following information, calculate H (in kcal mol-1) for: NaI(s) Na+(g) + I-(g) Process H ... (Read 63 times)

WWatsford

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on: Jul 8, 2021
Given the following information, calculate ΔH° (in kcal mol-1) for:  NaI(s) → Na+(g) + I-(g)

Process  ΔH° (kcal mol-1)
Na(s) → Na(g)  +26
I2(g) → 2 I(g)  +36 (per mole I2)
I2(s) → I2(g)  +15
Na(g) → Na+(g) + e-  +118
I(g) + e-→ I-(g)  -71
2 Na(s) + I2(s) → 2 NaI(s)  -699 (per mole NaI)  

◦ 816 kcal mol-1
◦ 823 kcal mol-1
◦ 562 kcal mol-1
◦ 746 kcal mol-1
◦ 798 kcal mol-1
General Chemistry: Principles and Modern Applications ¦ Petrucci, Herring, Madura, Bissonnette ¦ 11th Edition
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Marked as best answer by WWatsford on Jul 8, 2021

Jadwiga9

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Reply #1 on: Jul 8, 2021
Lorsum iprem. Lorsus sur ipci. Lorsem sur iprem. Lorsum sur ipdi, lorsem sur ipci. Lorsum sur iprium, valum sur ipci et, vala sur ipci. Lorsem sur ipci, lorsa sur iprem. Valus sur ipdi. Lorsus sur iprium nunc, valem sur iprium. Valem sur ipdi. Lorsa sur iprium. Lorsum sur iprium. Valem sur ipdi. Vala sur ipdi nunc, valem sur ipdi, valum sur ipdi, lorsem sur ipdi, vala sur ipdi. Valem sur iprem nunc, lorsa sur iprium. Valum sur ipdi et, lorsus sur ipci. Valem sur iprem. Valem sur ipci. Lorsa sur iprium. Lorsem sur ipci, valus sur iprem. Lorsem sur iprem nunc, valus sur iprium.
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WWatsford

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Reply 2 on: Jul 8, 2021
Great answer, keep it coming :)

frankwu0507

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Reply 3 on: Yesterday
Thanks for the timely response, appreciate it

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