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Author Question: Quadratics stretching and vertex form help? (Read 3448 times)

federox

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  • Posts: 308
on: Jun 18, 2013
Hi, so the questions tells me to...
Evaluate the following function at 3,-3,0, and z
D(r)= -(r-2)^2+8
I got the correct answers for the first three numbers but got "z" incorrect. Can someone please show me how to get the correct answer?

This is what I did...
D(z)= -(z-2)^2+8
= -z^2+4+8
= -z^2+12


curlz

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  • Posts: 538
Reply #1 on: Jun 18, 2013
-(r-2)^2+8=
-[r^2-4r+4]+8=
-r^2+4r+4


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